3.55x^2+9x=0

Solution for 3.55x^2+9x=0 equation:

3.55x^2+9x=0

a = 3.55; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·3.55·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*3.55}=\frac{-18}{7.1}
=-2+2.11111111111/3.94444444444
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*3.55}=\frac{0}{7.1}
=0
$